Question

The perimeter of a rhombus whose diagonals are of l 10 cm and 24 cm is ?

Answer 1

Not that hard as u think.

First u should know the properties of rhombus.

For this question u need to know these 2 properties:

1. All sides of rhombus are equal.

2. Diagonals of rhombus bisect each other.

Now, let’s come to the question.



For understanding this question we will take help of this rhombus

According to question,

AC= 24 cm and BD=10 cm

we need to find the perimeter

AE=EC=12 cm and BE=ED=5 cm (Property 2)

Now, in triangle AED, By Pythagoras Theorem

AD^2= AE^2 + ED^2

AD^2= 12^2 + 5^2

AD^2= 144 + 25

AD^2= 169

AD = 13 cm

Perimeter = AB+BC+CD+DA = 13+13+13+13= 52cm (Property 1)

Upvote if u understood