Question

The perimeter of a right angle triangle is 24 cm.If its hypotenuse is 10 cm .Find the area of triangle

Answer 1

perimeter of right angle triangle=×+×+×
24=3×
×=8cm
area of triangle=1/2×base×hypotenuse
=1/2×8×10
=40cm^2

Answer 2

let the height and base be a and b
a^2+b^2=10^2=100........(.1)
a+b=24-10=14
(a+b)^2=196
a^2+b^2+2ab=196
100+2ab=196........from 1
ab=48

area of triangle=ab/2=48/2=24sq.cm