Question

The perimeter of a right angle
triangle is 24cm. If its hypotenuse
is 10cm, find its area​

Answer 1

⚛⚛⚛Hеч мате⚛⚛⚛

нᰀᰍᰀ ꤞꤥꤢꤔ ꤟꤥꤓᰍ ꤌꤡꤔᰃᰀᰍ⤵⤵⤵

as

a+b =14 cm

a^2 + b ^2 =100

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ 196 = 100 + 2ab \\ 96 = 2ab \\ 48 = ab$

area of triangle = 1/2 × b × h

base =b

height =a

$= \frac{1}{2} \times a \times b \\ = \frac{1}{2} \times 48 \\ = 24$

☄☄ꤌᰍᰀꤌ ꤥf triangle is 24 cm sq.☄☄

⚛⚜⚜hꤥꤐꤢ it hꤢlpꤔ ꤣ⚜⚜⚛

Answer 2

Answer:

Perimeter= 24cm

a+b+c= 24

a+b+10= 24

a+b=24-10

a+b= 14

And also a^2+b^2=10^2=100

So,

(a+b)^2=a^2+b^2+2ab

14^2 = 10^2+2ab

196 = 100+ 2ab

2ab= 196-100

2ab= 96

ab= 96/2

ab= 48

So, area= 1/2*b*h

= 1/2*a*b

=1/2*48

=24cm^2

Therefore answer is 24cm^2

Thank you