the perimeter of a right angle triangle is 30 cm its hypotenuse is 13 cm then what are two sides
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by applying pythagoras theoram we can solve this problem
ranjith12352:
can solve it and show me
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Perimeter of right angle triangle=a+b+✓a²+b²
30=13+b✓30²+b²
30-13=b+✓900+b²
17²=b+900+b²
289=b+900+b²
b²+b+900-289=0
Apply the formula of factorisation
b=-1+-√1²-4×1×611/2×1
b=-1+-√1-2444/2
b=-1+-√-2443/2
b=-1+(-49.4267134)/2 or, b=. -1-(-49.4267134)
b=-50.4267134/2 or, b=48.4267134/2
b=-25.2133567. or, b= 24.2133567
b=-25(approx). Or, b= 24(approx)
We know that side never be negative..
Then b=24
So, third side c²=b²- a²
c²=24²-13²
c²=576-169
C=√407
C=20.174241
So, c=20(approx)
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