the perimeter of a right angle triangle is 40 cm if its hypotenuse is 17 cm find the area ...
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Answers
Answer:
The perimeter of a right triangle =40cm
Hypotenuse measures =17cm.
Let x and y are the another sides.
40=17+x+y
x+y=23
or y=23−x
So, we have 3 sides as x,23−x and 17.
Apply Pythagoras theorem:
Hypotenuse
2
= Base
2
+ Perpendicular
2
17
2
=x
2
+(23−x)
2
289=x
2
+529+x
2
−46x
x
2
−23x+120=0
(x−8)(x−15)=0
x=8 or x=15
If x=8 then y=23−8=15
If x=15 then y=23−15=8
Now,
Area of triangle =
2
1
×base×height
=
2
1
×8×15
=60
Therefore, Area of triangle is 60cm
2
Step-by-step explanation:
let x &y be another sides
40=17+x+y
23=x+y
y=23-x
now three sides are x, 23-x,17
by pythogoras theorem
hypotenuse ^2 =base^2+perpendicular side^2
17^2=x^2+23-x^2
289=x^2+529-46x+x^2
x^2-23x+120=0
(x-15) (x-8)
x=15 or x=8
y= 23-15
y=8
if we had chossen x =8
y =23-8
y =15
area of triangle = 1/2 × base ×height
= 1/2 ×8×15
=60cm^2