the perimeter of a right angle triangle is 60 cm it is hyotenuse 25 cm find other two sides
Answers
Answer:
perimeter of that triangle = 60cm
the measure of hypotaneous = 25cm
then the rest sides must measure = 60-25
= 35
let one side be x
then, thw measure of the third side must be 35 - x
using pythagoras theorem
(25)^2 =(x)^2 + (35-x)^2
625 = x^2 + x^2 - 70x + 1225
x^2 + x^2 - 70x + 1225 = 625
x^2 + x^2 - 70x + 1225 -625 = 0
2 x^2 - 70x + 600 = 0
2x^2 - 40x - 30 x + 600= 0
2x (x-20) -30 ( x - 20) = 0
(x-20)(2x-30)=0
x -20 = 0
x = 20
2x -30 =0
2x =30
x = 15
so,
one of the side measure either 20 cm 15 cm
if one side measure 20cm then the other must measure 35 -20 = 15cm
and if it measured 15 cm then the other side measure 35-15 = 20 cm
so,
we will get 20cm and 15 cm as our remaining sides.
one of then will be height and the other misy be the base,
now apply the formula of area of triangle i.e
(1/2) (height)(base)
= (1/2 )(20)(15)
= 150 cm^2
so, the area of that triangle will be 150 cm^2.
Step-by-step explanation:
Answer:
here is your answer mate
Step-by-step explanation:
perimeter of that triangle = 60cm
the measure of hypotenuse = 25cm
then the rest sides must measure = 60-25
= 35
let one side be x
then, the measure of the third side must be 35 - x
using the Pythagorean theorem
(25)^2 =(x)^2 + (35-x)^2
625 = x^2 + x^2 - 70x + 1225
x^2 + x^2 - 70x + 1225 = 625
x^2 + x^2 - 70x + 1225 -625 = 0
2 x^2 - 70x + 600 = 0
2x^2 - 40x - 30 x + 600= 0
2x (x-20) -30 ( x - 20) = 0
(x-20)(2x-30)=0
x -20 = 0
x = 20
2x -30 =0
2x =30
x = 15
so,
one of the side measure either 20 cm 15 cm
if one side measure 20cm then the other must measure 35 -20 = 15cm
and if it measured 15 cm then the other side measure 35-15 = 20 cm
so,
we will get 20cm and 15 cm as our remaining sides.
one of then will be height and the other will be the base,
now apply the formula of area of triangle that is
(1/2) (height)(base)
= (1/2 )(20)(15)
= 150 cm^2
so, the area of that triangle will be 150 cm^2.