Math, asked by AddsWorld, 1 month ago

The perimeter of a right angled triangle is 32 cm.Its height and hypotenuse measures 10 cm and 13 cm respectively.Find its area.
Please give full solution. ​

Answers

Answered by sushant8a
3

 According \: to \: the \: question

 Perimeter \: of \: triangle = 32\:cm.

 Height \: of\: triangle = 10\:cm.

 Hypotenuse \: of \: triangle = 13\:cm.

 Let \: the \: base \: be = b.

10 + 13 + b = 32 \: cm

 \:  \:  \:  \:  \:  \:  \:  \:  \:  23 + b = 32

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  b = 32 - 23

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 9

Area \: of \: triangle = \frac{1}{2} ×b×h

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{1}{2}  \times 10 \times 9

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  5 \times 9

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 45

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 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: brainliest \: answer.

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