The perimeter of a right angled triangle is 48 centimetres and its area is 96 square centimetres. Length of the hypotenuse is 20 centimetres
What are the lengths of the perpendicular sides ?
pls help
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2
Answer:
16 and 12
Step-by-step explanation:
let say those sides are a, b, c
and c is the hypotenuse
so c=20
so perimeter =a+b+c=48
a+b +20=48
a+b=48-20=28
a+b=28---eq1
and area of a right triangle = 1/2 * product of two perpendicular lines, in this case a and b
1/2ab=96
ab= 96*2= 192
we know a+b and ab
in order to find a-b use
(a+b)^2-4ab= (a-b) ^2
so
28^2-4*192=(a-b) ^2
784-768= (a-b) ^2
(a-b) ^2=16
so a-b =4---eq2
from eq1 and eq2
a+b=28
a-b=4
add both of them
2a=32
a=16
so b= 12
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