Question

* The perimeter of a right triangle is 12 cm, its hypotenuse is 5 cm and base is 4 cm. Find the area of the triangle​

Answer 1

Answer:

6 sq.cm

Step-by-step explanation:

Perimeter of a triangle = sum of all sides

12=5+4+height

12-9=height

3cm=height

Area of triangle =1/2*base *height

=1/2*4*3

=6 sq.cm

Answer 2

The area of the right triangle is 6 cm².

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Let's understand a few concepts:

To solve the given problem we will use the following formulas:

• $\boxed{\bold{Perimeter\:of \:triangle = sum\: of\: all\:3\:sides}}$

• $\boxed{\bold{Area\:of \:triangle = \frac{1}{2} \times base \times height}}$

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Let's solve the given problem:

The perimeter of a right-angled triangle = 12 cm

The hypotenuse of the right-angled triangle = 5 cm

The base of the right-angled triangle = 4 cm

Therefore,

Perimeter of the right-angled triangle = Hypotenuse + Base + Height

$\implies 12 = 5 + 4 + Height$

$\implies 12 = 9 + Height$

$\implies Height = 12 - 9$

$\implies Height = 3\:cm$

Now,

The area of the right-angled triangle is,

= $\frac{1}{2} \times Base \times Height$

= $\frac{1}{2} \times 4 \times 3$

= $2\times 3$

= $\bold{6\:cm^2}$

Thus,  the area of the triangle​ is 6 cm².

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