Math, asked by badarunnisa8656, 10 months ago

The perimeter of a right triangle is 132cm and the sum of squares of its sides is 6050 . What is the sum of the perpendicular sides

Answers

Answered by thakuramarendra533
19

let the sides be a b and c where c is hypotenuse.

a²+b²=c²

the sum of squares of its sides is 6050 .

a²+b²+c²=6050

a²+b²+a²+b²=6050

2(a²+b²)=6050

a²+b²=3025

c²=3025

c=√3025=55

The perimeter of a right triangle is 132cm.

a+b+c=132

a+b+55=132

a+b=77

Answered by dradelink9
0

Step-by-step explanation:

let the sides be a b and c where c is hypotenuse.

a²+b²=c²

the sum of squares of its sides is 6050.

a²+b²+c²=6050 a²+b²+a2+b²=6050

2(a²+b²)=6050

a²+b²=3025

c²=3025

c=√3025=55

The perimeter of a right triangle is 132cm.

a+b+c=132

a+b+55=132

a+b=77

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