The perimeter of a right triangle is 60. the length of the perpendicular to the hypotenuse is 12 what is the area?
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h2= b2 + p2
(12)2= b2+p2
144=b2+p2
let base be x
x+p+h=60
x+p+12=60
p=48-×
by putting the value of p in the above equation u get the answer
(12)2= b2+p2
144=b2+p2
let base be x
x+p+h=60
x+p+12=60
p=48-×
by putting the value of p in the above equation u get the answer
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