Question

The perimeter of a room is 52 m. Its breadth is 10 m. Find its length and the area of the carpet required to cover the floor​

Answer 1

Answer:

length of room is 16m and area of the carpet required to cover the floor is 160 m^2

Answer 2

Answer:

Let x be the length

2(l+b)=52

2(x+10)=52

2x +20=52

2x =52-20

   =32

so, x= 32/2=16

therefore length=16 m

Area of the carpet= lb

                              =16 x 10=160 $m^{2}$

Step-by-step explanation:

length=16 m

area=160 $m^{2}$