Question

The perimeter of a school hall was 128 m. The length of the school hall was 38 m longer than the breadth. What was the area of the school hall?

Answer 1

✬ Area = 663 m² ✬

Step-by-step explanation:

Given:

• Perimeter of school hall was 128 m.
• Length of hall was 38 m longer then breadth.

To Find:

• What was the area of school hall ?

Solution: Let the breadth of school hall was b m. Therefore,

➟ Length = 38 more than b.

➟ Length = (b + 38)

Since the school is in rectangular shape so as we know that

★ Perimeter of Rectangle = 2(Length + Breadth) ★

A/q

• Perimeter = 128

$\implies{\rm }$ 128 = 2(b + 38 + b)

$\implies{\rm }$ 128 = 2(2b + 38)

$\implies{\rm }$ 128 = 4b + 76

$\implies{\rm }$ 128 – 76 = 4b

$\implies{\rm }$ 52 = 4b

$\implies{\rm }$ 52/4 = b

$\implies{\rm }$ 13 = b

So, measure of

• Breadth is 13 m.
• Length is 13 + 38 = 51 m

★ Ar. of Rectangle = Length × Breadth ★

$\implies{\rm }$ Area = 51 × 13

$\implies{\rm }$ 663 m²

Hence, area of school hall was 663 m².

Answer 2

$\huge\red{\mid{\fbox{\tt{Question}}\mid}}$

The perimeter of a school hall was 128 m. The length of the school hall was 38 m longer than the breadth. What was the area of the school hall?

$\huge\red{\mid{\fbox{\tt{Answer}}\mid}}$

Solution is given below ➡

Let B metre as the breadth of a school hall.

Length = 38 metres more than B.

Length = { b + 38 }

According to the question we find that the school is in Rectangular shape

$\bold{\pink{\fbox{\red{So we know that}}}}$

Perimeter of rectangle =

2 ( Length + Breadth )

Perimeter is given = 128 m

So,

➡ 128 = 2 ( b + 38 + b )

➡ 128 = 2 ( 2b + 38 )

➡ 128 ( 4b + 76 (

➡ 128 - 76 = 4b

➡ 52 = 4b

➡ B =

$\frac{52}{4} = 13$

So ,

Breadth = 13 metres.

Length = ( 13 + 38 )

= 51 metres

$\bold{\pink{\fbox{\red{So we know that}}}}$

Area of Rectangle =

Length × Breadth

13 × 51

663 m²

Answer = 663² is the area of given question .

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