Question

The perimeter of a school volley ball court is 177 ft and the length is twice the width . What are the dimension of the volley ball court ?​

Answer 1

Answer:

!

. =2 ⟶(1)

=177.

⇒2(+)=177

⇒2(2+)=177

⇒6=177

⇒=

6

177

=29.50

∴=2×29.50=59 .

∴ =59 =29.50.

Step-by-step explanation:

Answer 2

GivEn:

• The perimeter of a school volley ball court is 177 ft.
• The length of a school volley ball court is twice the width.

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To find:

• Dimensions of the volley ball court.

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SoluTion:

Volley ball court has Rectanglular shape.

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So,

☯ Let breadth of volley ball court be x ft.

☯ Therefore, Length of volley ball court is 2x ft.

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${\underline{\bf{\bigstar\;As\;per\;given\; Question\;:}}}$

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★ The perimeter of a school volley ball court is 177 ft.

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We know that,

$\;\;\;\star\;{\boxed{\bf{\purple{Perimeter_{\;(Rectangle)} = 2(l + b)}}}}$

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$\;\;\;\;\;\;\small\sf \underline{Putting\;values\;:}$

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$:\implies\sf 177 = 2(2x + x)$

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$:\implies\sf 177 = 4x + 2x$

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$:\implies\sf 177 = 6x$

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$:\implies\sf x = \dfrac{177}{6}$

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$:\implies{\underline{\boxed{\bf{\pink{29.8\;ft}}}}}\;\bigstar$

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Therefore,

• Breadth of volley ball court, x = 29.8 ft.
• Length of volley ball court, 2x = 2 × 29.8 = 59 ft.

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Additional Information:

• Area of Rectangle = l × b
• Area of square = side × side
• Perimeter of Square = 4 × side
• Area of Circle = πr²
• Circumference of Circle = 2πr