Question

The perimeter of a school volleyball court is 177ft and the length is twice the width what are the dimensions of the volleyball court ​

Answer 1

Given :

• Perimeter of school volleyball court = 177 ft
• Length is twice the width .

$\\ \rule{200pt}{3pt}$

To Find :

• Dimensions of the volleyball court = ?

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Solution :

~ Formula Used :

• Perimeter of Rectangle :

${\green{\dashrightarrow}} \: \: {\underline{\overline{\boxed{\orange{\pmb{\frak{ Perimeter = 2(L + B )}}}}}}}$

Where :

• ➳ L = Length
• ➳ B = Breadth or Width

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~ Calculating the Breadth :

${\pink{\leadsto}}$ Let the Breadth be y .So,

• ➳ Breadth = y
• ➳ Length = 2 × y

Let's Calculate :

${\longmapsto{\qquad{\sf{ Perimeter{\small_{(Volleyball \: Court)}} = 2(L + B) }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 177 = 2[( 2 \times y) + (y) ] }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 177 = 2(2y + y) }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 177 = 4y + 2y }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 177 = 6y }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ \cancel\dfrac{177}{6} = y}}}} \\ \\ \ {\qquad{\textsf{ Value of y = {\pink{\sf{ 29.5 }}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Dimensions :

${\color{red}{\underline{\underline{\purple{\sf{ Breadth = y = 29.5 \: feet }}}}}}$

${\color{red} {\underline{\underline{\purple{\sf{ Length = 2y = 2 \times 29.5 = 59 \: feet }}}}}}$

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Therefore :

❝ Length of the volleyball court is 59 ft and its width is 29.5 ft . ❞

$\\ {\green{\underline{\rule{75pt}{9pt}}}}{\color{maroon}{\underline{\rule{75pt}{9pt}}}}{\red{\underline{\rule{75pt}{9pt}}}}$

Answer 2

$\underline{ \pink{ \rm GIVEN \: \: DATA\: \: : }}$

Perimeter of a Rectangular Volleyball Court is 177ft.

Length is twice it's breadth.

$\underline{ \purple{ \rm TO \: \: FIND \: \: : }}$

Find it's Dimensions.

$\underline{ \red{ \rm SOLUTION \: \: : }}$

Let the Breadth be x

and, the Length be 2x

so,

By using the Perimeter Formula.

$\boxed{ \blue\ast \: \boxed{ \boxed{ \mathfrak{ \orange{Perimeter} = \green{ 2(l+b) }}}}}$

so, by Applying the Values,

$➻ \: \: \rm Perimeter = 2(2x + x)$

$➻ \: \: \rm 177 = 6x$

$➻ \: \: \rm x = \frac{177}{6}$

$➻ \: \: \boxed{ \color{green} \rm x = 29.5 \:ft}$

Now, Finding it's Dimensions :

$\sf Length = 2x = 59 ft$

$\color{maroon} \mathbf{⍟ \: \: Length \: \: of \: \:volleyball \: \: court \: \: is } \: \: \color{indigo}{ \rm 59ft}$

$\sf Breadth = x = 29.5ft$

$\color{darkgreen} \mathbf{⍟ \: \: Breadth \: \: of \: \: volleyball \: \: court \: \: is} \: \: \color{gold} \rm29.5ft$