the perimeter of a sector of a circle of radius 5.6cm is 27.2cm. find the area of sector
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radius= 5.6cm
perimeter of sector= 2r+ y/360x2x22/7xr where y= angle theeta or angle subtended at the centre of circle
27.2 = 2x5.6+ y/360x44x0.8
27.2x360= 11.2+35.2y
9792-11.2= 35.2y
9780.8= 35.2y
y= 277.86 (not sure about the answer but, this is the method...)
area of sector of circle= y/360x22/7xr2 where y= angle theeta or angle subtended at the centre of circle
= 277.86/360x22/7x5.6x5.6
= 0.77x22x0.8x5.6
=75.8 sq.cm ( should be the answer)
perimeter of sector= 2r+ y/360x2x22/7xr where y= angle theeta or angle subtended at the centre of circle
27.2 = 2x5.6+ y/360x44x0.8
27.2x360= 11.2+35.2y
9792-11.2= 35.2y
9780.8= 35.2y
y= 277.86 (not sure about the answer but, this is the method...)
area of sector of circle= y/360x22/7xr2 where y= angle theeta or angle subtended at the centre of circle
= 277.86/360x22/7x5.6x5.6
= 0.77x22x0.8x5.6
=75.8 sq.cm ( should be the answer)
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54
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