Question

The perimeter of a semicircle is 126m what is the area​

Answer 1

Step-by-step explanation:

perimeter= πr

126 = 22/7 * r

126*7÷22= r

r= 40 m

area=1/2 πr²

1/2*22/7*(40)²

=2514.2m²

Answer 2

Answer:

2525.72

Step-by-step explanation:

given,

semi-perimeter(s)= πr=126

or,r=126/π-----(1)

now,

area of semicircle(a)=(πr^2)/2

={π*(126/π)^2}/2--------from(1)

={ π*15876/π^2}/2

=2525.72