Question

The perimeter of a semicircular garden is 108 m. What is the area of this garden?​

Answer 1

Answer:

180

ok I will be there at Jyotiprasad a few days ago to see

Answer 2

Answer:

Step-by-step explanation:

Let radius of the garden ▶ r

Given, perimeter ▶ 108

=> Diameter of the garden + semi-circumference of the garden = 108

So,

=> 2r + πr = 108

=> r(2 + π) = 108

=> r(2 + 22/7) = 108

=> r(14 + 22)/7 = 108

=> 36r/7 = 108

=> r/7 = 108/36

=> r/7 = 3

=> r = 3×7

=> r = 21

Area of garden=πr²/2 =(22/7)×(21×21)/2

After solving we will get 693

So the answer will be 693m²