Question

The perimeter of a semicircular path is 108 m find the area of this semicircular path

Answer 1

Answer:

693m$x^{2}$

Step-by-step explanation:

P = 108m

P = r($\pi$+2)

108 = r(22/7+2)

108 = r(36/7)

108*7 = 36r

756 = 36r

r = 756/36

r = 21m

A = 1/2$\pi$r$x^{2}$

   = 1/2*22/7*21$x^{2}$

   =1 1/7*441

   =  11*63

A = 693m$x^{2}$