The perimeter of a semicircular path is 108 m find the area of this semicircular path
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Answer:
693m
Step-by-step explanation:
P = 108m
P = r(+2)
108 = r(22/7+2)
108 = r(36/7)
108*7 = 36r
756 = 36r
r = 756/36
r = 21m
A = 1/2r
= 1/2*22/7*21
=1 1/7*441
= 11*63
A = 693m
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