Math, asked by anushka254265, 9 months ago

the perimeter of a semicircular plate is 108cm.find it's area.​

Answers

Answered by harshit9353
20

Answer:

hope it helps you dear

Step-by-step explanation:

The perimeter = (pi)r + 2r where r is the radius. Here

r[(22/7) + 2] = 108, or

r = 108/[(22/7) + 2] = 21

So the area of the semicircle is (pi)*(21^2)/2 = 693 sq cm.

plz Mark as brainlist

plz follow me


harshit9353: plz Mark as brainlist answer
tirshabiswasruli2018: perimeter = pi x r + 2r = r (pi+2)

=108

r x (22/7+2)

r x (36/7) = 108

r = 21cm

area = pi x r^2/2

= 22/7 x 21^2/2

= 11*21*3

= 693 sq.cm

The perimeter = (pi)r + 2r where r is the radius. Here

r[(22/7) + 2] = 108, or

r = 108/[(22/7) + 2] = 21

So the area of the semicircle is (pi)*(21^2)/2 = 693 sq cm.
harshit9353: my answer is same
Answered by pinquancaro
12

The area of the semicircular plate is 1386 cm².

Step-by-step explanation:

Given : The perimeter of a semicircular plate is 108 cm.

To find : It's area. ?

Solution :

The perimeter of the semi circle is P=\pi r+2r.

The perimeter of a semicircular plate is 108 cm.

i.e. \pi r+2r=108

r(\pi+2)=108

r=\frac{108}{\frac{22}{7}+2}

r=\frac{108\times 7}{36}

r=21

The area of the circle is A=\pi r^2

A=\frac{22}{7}\times 21^2

A=1386\ cm^2

Therefore, the area of the semicircular plate is 1386 cm².

#Learn more

Area of semicircle and perimeter of semicircle​

https://brainly.in/question/9802311

Similar questions