the perimeter of a sheet of a paper in the shape of a quadrant of a circle is 75 cm.find its area.
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41
Given,
area of quadrant=75 cm
then,
1/4×2πr=75
1/2×22/7×r=75
r=75×7/22×2
r=47.73 cm
area of quadrant=1/4×π(r×r)
=1/4×22/7×(47.73×47.73)
=1/2×11/7×(2,278.153)
= 1,789.98 sq.cm.
area of quadrant=75 cm
then,
1/4×2πr=75
1/2×22/7×r=75
r=75×7/22×2
r=47.73 cm
area of quadrant=1/4×π(r×r)
=1/4×22/7×(47.73×47.73)
=1/2×11/7×(2,278.153)
= 1,789.98 sq.cm.
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