the perimeter of a square ABCD is 12 more than of a square pqrs if the area of a square is 11 less than thrice the area of second square find the perimeter of second square
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let the side of square ABCD be x
let the side of square PQRS be y
4x=12+4y
x=12+4y
4
x=4(3+y)
4
4 cancel 4
x=(3+y)
Area of sq ABCD = 3*area of sq PQRS-11
x2=3y2-11
(3+y)2=3y2-11
9+y2+6y=3y2-11
=3y2-y2-6y-11-9
=2y2-6y-20
divided by 2
=y2-3y-10
=y2+2y-5y-10
=y(y+2)-5(y+2)
=(y+2)(y-5)
y=5
perimeter of the second square is
=4y
=4(5)
=20
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