The perimeter of a square ABCD is 64 cm having its diagonal AC and BD Find (AC) ^2 +(BD)^2.
Answers
Answered by
2
Perimeter of square = 64 cm
Side of square = 64 / 4 = 16 cm
Diagonal = side × root2 = 16 root2
AC = 16 Root2
BD = 16 root2
AC^2 + BD^2 = 2× (16 root2) ^2
= 2 × 256 × 2
= 4 × 256
= 1024
Side of square = 64 / 4 = 16 cm
Diagonal = side × root2 = 16 root2
AC = 16 Root2
BD = 16 root2
AC^2 + BD^2 = 2× (16 root2) ^2
= 2 × 256 × 2
= 4 × 256
= 1024
Answered by
4
hope it will help u.. for further maths problem.. u will text me private
Attachments:
Similar questions