the perimeter of a square and a rectangle are equal the length and breadth of rectangle are 52 CM 36 cm find which figure has greater area
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Answer:
Square
Step-by-step explanation:
Lenght of rectangle=52 cm
Breadth of rectangle=36 cm
Perimeter of rectangle=2(l+b)
=2(52+36)
=2(88)
=176 cm
So, perimeter is square(4×side)=176 [let side be s]
So, 4s=176
s=176/4
s=44cm
Now, finding their areas we get,
Area of rectangle =(l×b)
=(52×36)
=1872cm^2
Area of square =(s^2)
=(44^2)
=1936 cm^2
Since, 1936 cm^2 > 1872 cm^2,the area of the square is greater than the area of the rectangle.
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