Question

The perimeter of a square and rectangle are equal.if the perimeter of the square is 40cm and length of rectangle is 2cm more than the side of the square .then find the area of the rectangle in cm^²​

Answer 1

Answer:

96 cm^2

Step-by-step explanation:

perimeter of square=40

side of square=40/4=10

length of rectangle =10+2=12

perimeter of rectangle =40

2(L+B)=40

2(12+B)=40

B=8

area of rectangle=12*8=96cm^2

Answer 2

Answer:

The perimeter of a square and rectangle are equal.

If the perimeter of the square is 40cm.

$4a = 40 \\ a = 10 \: cm$

length of rectangle is 2cm more than the side of the square.

$l = a + 2 = 10 + 2 = 12 \: cm$

Perimeter of rectangle,

$2l + 2b = 40 \\ 2 \times 12 + 2b = 40 \\ 24 + 2b = 40 \\ 2b = 16 \\ b = 8 \: cm$

The area of the rectangle in cm^²

$area = 12 \times 8 = 96 \: {cm}^{2}$