Question

The perimeter of a square and the perimeter of a triangle is the same. The side length of a side of the square is 3x + 3. The triangle has 2 sides with a length of 7x - 2 and the
third side with a length of 2x + 4. What’s the perimeter of the square and the triangle?

Answer 1

Answer:

48

Step-by-step explanation:

The formula to calculate *the perimeter of square is =a+a+a+a=4a*. where a is the side length of the square and you definitely know that a square has 4 equal sides , don't you?

To calculate the perimeter of triangle is to add up its three sides' lengths .

Now , let's come to your question.

Main Ans:---

The side length of the square = 3x+3 [ x>0]

perimeter of the square= 4*(3x+3)=12x+12

The length of the sides of the triangle are respectively (7x-2),(7x-2),(2x+4).

Perimeter of the triangle= (7x-2)+(7x-2)+(2x+4)= 2*(7x-2)+(2x+4)=14x-4+2x+4=16x

By the question ,

Perimeter of the square=Perimeter of the triangle

or, 12x+12=16x

or,16x-12x=12

or,4x=12

or,x=3

Therefore,

Perimeter of the square=Perimeter of the triangle=16x=16*3=48

That's the answer.

Answer 2

Answer ☜☆☞

48

Step-by-step explanation ☜☆☞

To Find ☞

The perimeter of the square and the Triangle

Solution ☞

First,

Perimeter of the square = 4 × sides

$= 4(3x + 3)$

$= 12x + 12$

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Perimeter of the triangle =(side + side + side)

$= 2(7x - 2) + 2x + 4$

$= (14x -4) + 2x + 4$

$= 14x + 2x - 4 + 4$

$= 16x$

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Given,

$12x + 12 = 16x$

$= > 12 =16 x - 12x$

$= > 12 = 4x$

$= > 4x = 12$

$= > x = \frac{12}{4}$

$= > x = 3$

________________________________

Since,

x=3

Therefore,

Perimeter of the square

= 4(3×3)+3)

=4(9+3)

=4×12

=48

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perimeter of the triangle

=(14×3)-4)+(2×3)+4)

=(42-4)+(6+4)

=38+10

=48

________________________________

☜☆ Hope it helps☆☞