Math, asked by fauzia63, 2 days ago

The perimeter of a square cardboard is 1m. Find its area in cm2




please answer me step - by - step explantation like how to find the length , breadth , etc .​

Answers

Answered by manishaudugu
0

Answer:

Area=0.063m2

Step-by-step explanation:

let side of square cardboard be a.

we know that,

perimeter of square=4×side

There fore:4×a

=1m

4×a=100cm

a=100/4

a=25cm

Areaof Square=Side×Side

Area=25×25=625cm2.

Answered by AnanyaBaalveer
3

\huge\underline{\sf{Solution \implies}}

\large\underline{\sf{given:perimeter \: of \: square}}

____________________

\large\underline{\sf{to \: find: area_{square}}}

____________________

\large\underline{\sf{formula \: used \rightarrow \:  {(side)}^{2} }}

_____________________

\large\underline{\sf{1m = 100cm}}

\large\underline{\sf{ area_{square} =  {side}^{2} }}

\large\underline{\sf{area_{square}  = 100 {cm}^{2} }}

\large\underline{\sf{( {side)}^{2} =  {100cm}^{2}  }}

\large\underline{\sf{side =  \sqrt{100 {cm}^{2} } }}

\large\underline{\sf{side = 10cm}}

___________________

\large\underline{\sf{area \: formulas}} \\  \star \large\underline{\sf{square \rightarrow  {side}^{2} }} \\ \large\underline{\sf{ \star rectangle \rightarrow length \times breadth}} \\ \large\underline{\sf{ \star scalene \triangle \rightarrow  \sqrt{s(s -a )(s - b)( s- c)} }} \\ \large\underline{\sf{ \star \: isosceles \triangle \rightarrow  \frac{1}{2} \times base \times height }}

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