Question

the perimeter of a square field is 444m, find the area of the field. also find the cost of ploughing the field at rs 35 per m²​

Answer 1

$\huge \underline{ \rm{Answer}}$

$\large \underline{ \underline{ \frak{ \color{magenta}Given::}}}$

${ \mapsto \sf{Perimeter \: of \: square \: field=444m}}$

${ \mapsto \sf{Cost \: of \: plughing \: square \: field=35 \: per \: {m}^{2} }}$

$\large \underline{ \underline{ \frak{ \color{black}To \: find::}}}$

$\leadsto \sf{Area \: of \: square \: field. }$

${ \leadsto \sf{Cost \: of \: ploughing \: the \: square \: field. }}$

$\large \underline{ \underline{ \frak{ \color{peru}Formula \: required::}}}$

$\dag {\underline \blue { \boxed{ \rm \green {Side \: of \: square \: field= \frac{Perimeter}{4} }}}}$

$\dag \underline{ \red{ \boxed{ \rm \green{Area \: of \: square \: field= {(side)}^{2} }}}}$

$\large \underline{ \underline{ \frak{ \color{indigo}According \: to \: Question::}}}$

${{ \dashrightarrow{ \sf{Side \: of \: square \: field= \frac{Perimeter}{4} }}}}$

${{ \dashrightarrow{ \sf{Side \: of \: square \: field= \frac{444}{4}m }}}}$

${{ \dashrightarrow{ \sf{Side \: of \: square \: field= \cancel\frac{444}{4}m }}}}$

${{ \dashrightarrow{ \sf{Side \: of \: square \: field= 111m }}}}$

$\bf \underline{Again, }$

${ { \dashrightarrow{ \sf{Area \: of \: square \: field= {(side)}^{2} }}}}$

${ { \dashrightarrow{ \sf{Area \: of \: square \: field= {(111m)}^{2} }}}}$

${ { \dashrightarrow{ \sf{Area \: of \: square \: field=12,321 {m}^{2} }}}}$

$\bf \underline{Then, }$

${ \dashrightarrow \sf{Cost \: of \: ploughing \: the \: square \: field =₹( 35 \times Total \: area \: of \: square \: field )}}$

${ \dashrightarrow \sf{Cost \: of \: ploughing \: the \: square \: field = ₹(35 \times 12,321 {m}^{2} ) }}$

${ \dashrightarrow \sf{Cost \: of \: ploughing \: the \: square \: field =₹4,31,235}}$

$\bf \underline{Hence, }$

$\: \: \: \: \: \star\underline{ \red{ \boxed{ \rm \green{Area \: of \: square \: field=12,321 {m}^{2} }}}}$

$\: \: \: \: \: \star\underline{ \blue{ \boxed{ \rm \green{Cost \: of \: ploughing \: the \: square \: field=₹4,31,235}}}}$

Answer 2

Step-by-step explanation:

$\huge \underline{ \rm{Answer}}Answer</p><p></p><p>\large \underline{ \underline{ \frak{ \color{magenta}Given::}}}Given::</p><p></p><p>{ \mapsto \sf{Perimeter \: of \: square \: field=444m}}↦Perimeterofsquarefield=444m</p><p></p><p>{ \mapsto \sf{Cost \: of \: plughing \: square \: field=35 \: per \: {m}^{2} }}↦Costofplughingsquarefield=35perm2</p><p></p><p>\large \underline{ \underline{ \frak{ \color{black}To \: find::}}}Tofind::</p><p></p><p>\leadsto \sf{Area \: of \: square \: field. }⇝Areaofsquarefield.</p><p></p><p>{ \leadsto \sf{Cost \: of \: ploughing \: the \: square \: field. }}⇝Costofploughingthesquarefield.</p><p></p><p>\large \underline{ \underline{ \frak{ \color{peru}Formula \: required::}}}Formularequired::</p><p></p><p>\dag {\underline \blue { \boxed{ \rm \green {Side \: of \: square \: field= \frac{Perimeter}{4} }}}}†Sideofsquarefield=4Perimeter</p><p></p><p>\dag \underline{ \red{ \boxed{ \rm \green{Area \: of \: square \: field= {(side)}^{2} }}}}†Areaofsquarefield=(side)2</p><p></p><p>\large \underline{ \underline{ \frak{ \color{indigo}According \: to \: Question::}}}AccordingtoQuestion::</p><p></p><p>{{ \dashrightarrow{ \sf{Side \: of \: square \: field= \frac{Perimeter}{4} }}}}⇢Sideofsquarefield=4Perimeter</p><p></p><p>{{ \dashrightarrow{ \sf{Side \: of \: square \: field= \frac{444}{4}m }}}}⇢Sideofsquarefield=4444m</p><p></p><p>{{ \dashrightarrow{ \sf{Side \: of \: square \: field= \cancel\frac{444}{4}m }}}}⇢Sideofsquarefield=4444m</p><p></p><p>{{ \dashrightarrow{ \sf{Side \: of \: square \: field= 111m }}}}⇢Sideofsquarefield=111m</p><p></p><p>\bf \underline{Again, }Again,</p><p></p><p>{ { \dashrightarrow{ \sf{Area \: of \: square \: field= {(side)}^{2} }}}}⇢Areaofsquarefield=(side)2</p><p></p><p>{ { \dashrightarrow{ \sf{Area \: of \: square \: field= {(111m)}^{2} }}}}⇢Areaofsquarefield=(111m)2</p><p></p><p>{ { \dashrightarrow{ \sf{Area \: of \: square \: field=12,321 {m}^{2} }}}}⇢Areaofsquarefield=12,321m2</p><p></p><p>\bf \underline{Then, }Then,</p><p></p><p>{ \dashrightarrow \sf{Cost \: of \: ploughing \: the \: square \: field =₹( 35 \times Total \: area \: of \: square \: field )}}⇢Costofploughingthesquarefield=₹(35×Totalareaofsquarefield)</p><p></p><p>{ \dashrightarrow \sf{Cost \: of \: ploughing \: the \: square \: field = ₹(35 \times 12,321 {m}^{2} ) }}⇢Costofploughingthesquarefield=₹(35×12,321m2)</p><p></p><p>{ \dashrightarrow \sf{Cost \: of \: ploughing \: the \: square \: field =₹4,31,235}}⇢Costofploughingthesquarefield=₹4,31,235</p><p></p><p>\bf \underline{Hence, }Hence,</p><p></p><p>\: \: \: \: \: \star\underline{ \red{ \boxed{ \rm \green{Area \: of \: square \: field=12,321 {m}^{2} }}}}⋆Areaofsquarefield=12,321m2</p><p></p><p>\: \: \: \: \: \star\underline{ \blue{ \boxed{ \rm \green{Cost \: of \: ploughing \: the \: square \: field=₹4,31,235}}}}⋆Costofploughingthesquarefield=₹4,31,235</p><p></p><p>$