Question

The perimeter of a square field is (4x+8). find the length of its diagonal​

Answer 1

Answer:

$\sqrt{2}$(x+2)

Step-by-step explanation:

let side of square be a.

Then 4a = 4x + 8

therfore, a = x + 2.

Diagonal of a square = $\sqrt{2}$a = $\sqrt{2}$(x+2)

Answer 2

Perimeter of square= 4a

4a= 4x+8

4a= 4(x+2)

a = x+2

Length of diagonal=√2 a

= (x+2)√2

Note : a = side of square