The perimeter of a square Is 12 cm and that of another square is 16 cm. Find the perimeter of a square whose area is equal to the sum of the area of given two square
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Answer:
let the side of larger square be a and the other two be a₁ and a₂
perimeter of square=4 x side(formula)
∴ for 1st square
4a₁=12 cm
a₁=3 cm
a²₁=9 cm² (area of square= side²)
for 2nd square
4a₂=16 cm
a₂=4 cm
a²₂= 16 cm²
according to question,
a²=a₁²+a₂²
=9 + 16 cm²
=25 cm²
or, a = 5 cm
or, 4a= 20 cm
Step-by-step explanation:
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