the perimeter of a square is 24m and that of another is 32m find the perimeter of square which is equal to the area of these two.
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first you do=4×24 then 4×32 then you add mean that + it is the right answer
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perimeter of | square=4a=24
therefore, a=6
perimeter of || square=4a=32
therefore, a=8
area of first square =a×a=6×6=36 sq.m
area of second square=a×a=8×8=64 sq.m
sum of areas of both square=(36+64)sq. m
=100 sq.m
therefore the side of the square with area 100 sq.m will be √100=10
hence the perimeter of the square whose area is equivalent to both square=4a=4×10
=40m
so,the required perimeter of square whose area is equivalent to sum of both square is 40m
hope it helps you... please mark my answer as brainliest and start following me ☺️
therefore, a=6
perimeter of || square=4a=32
therefore, a=8
area of first square =a×a=6×6=36 sq.m
area of second square=a×a=8×8=64 sq.m
sum of areas of both square=(36+64)sq. m
=100 sq.m
therefore the side of the square with area 100 sq.m will be √100=10
hence the perimeter of the square whose area is equivalent to both square=4a=4×10
=40m
so,the required perimeter of square whose area is equivalent to sum of both square is 40m
hope it helps you... please mark my answer as brainliest and start following me ☺️
yuvsingh1705:
please mark my answer as brainliest and start following me
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