Question

The perimeter of a square is 26 CM, why the area of another square is 121 CM square. Find the ratio of their lengths.

Answer 1

Correct question: The perimeter of a square is 26 cm, while the area of another square is 121 cm square. Find the ratio of their sides.

Answer:

13:22

Step-by-step explanation:

Let the side of one square be x and the side of other square be y.

Given that -

Perimeter of first square = 26 cm

⇒ 4 * side = 26

⇒ Side = $\dfrac{26}{4}$

Area of second square = 121 cm²

⇒ (Side)² = 121

⇒ Side = √121

⇒ Side = 11 cm

To find: Ratio of Side of both the squares.

$= \sf \frac{side \: of \: first \: square}{side \: of \: second \: square} \\ \\ \sf = \frac{26}{4} \div 11 \\ \\ \sf = \frac{26}{4} \times \frac{1}{11} \\ \\ \sf = \frac{26}{44} \\ \\ \sf = \frac{13}{22}$

∴ Required ratio = 13:22

Answer 2

your question must be

The perimeter of a square is 26 cm², while the area of another square is 121 CM square. Find the ratio of their lengths.

Answer:

ratio = 13:22

Step-by-step explanation:

given that perimeter of a square = 26 cm

perimeter of square = 4 × side

ATQ,

4 × side = 26

side = 26/4

now,

given area of another square = 121 cm²

area of square = side²

ATQ,

side² = 121

side = √121

side = 11 cm

now,

ratio of length

side of 1st square/side of 2nd square

= 26/4/11

= 13/22

so,

ratio = 13:22