Question

The perimeter of a square is 26cm,wle the are of another square is 121cm². Find the ratio of their lengths.

Answer 1

Hi mate !!


Let the lenght of side of the first square be a and second square be b


Perimeter of 1st square = 26

4a = 26

a = 26/4

a = 13/2


Area of second square = 121

b² = 121

b = ± 11

b = 11 [ length can't be negative ]

$\frac{length \: of \: 1st}{lengh \: of \: 2nd} = \frac{a}{b} = \frac{ \frac{13}{2} }{11}$


$= \frac{13}{2} \times \frac{1}{11} = \frac{13}{22}$

The ratio of their side is a:b = 13:22