Question

The perimeter of a square is 28cm.Find its area and length of its diagonal.

Answer 1

HI DUDE....
Perimeter of square = 4×side
28 = 4×side
side = 28/4 = 7
Area of square = side × side = 7×7 = 49

Area of square = 1/2×(diagonal)²
49 = 1/2×(diagonal)²
Diagonal ² = 49×2 = 98
Diagonal = ✓98 = 9.8cm

HOPE THIS HELPS....
@HARSHA

Answer 2

Step-by-step explanation:

Given:

• Perimeter of square is 28 cm.

To Find:

• What is measure are of square and and length of its diagonal?

Solution: We know that

★ Perimeter of Square = 4 x Side ★

A/q

$\small\implies{\sf }$ 28 = 4 x Side

$\small\implies{\sf }$ 28/4 = Side

$\small\implies{\sf }$ 7 cm = Side

Hence, The length of each side of Square is 7 cm

★ Area of Square =( Side x Side ) ★

$\small\implies{\sf }$ Area of Square = (7 x 7)

$\small\implies{\sf }$ Area of Square = 49 cm²

• There is an another formula for finding area of square •

★ Area of Square = 1/2 x (Diagonal)² ★

$\small\implies{\sf }$ 49 = 1/2 x (D)²

$\small\implies{\sf }$ 49 x 2 = D²

$\small\implies{\sf }$ 98 = D²

$\small\implies{\sf }$ √98 = D

$\small\implies{\sf }$ 9.8 cm = D

Hence, The length of diagonal of square is 9.8 cm