Question

the perimeter of a square is 4(p+3q).find its area.

Answer 1

Answer: given perimeter is 4(p+3q)

It means side of square is p+3q.

Area of square is a^2.

A=(p+3q)^2

A=p^2+9q^2+6pq

Answer 2

Let the side be a
Perimeter of square is 4a = 4(p+3q)
4a = 4(p+3q)
a =(p+3q)
$area \: = {a}^{2} \\ {a}^{2} = {(p + 3q)}^{2} \\ area \: = {p}^{2} + 9 {q}^{2} + 6pq$