English, asked by O0oo0oo0oo0O, 11 months ago

The perimeter of a square is 44 cm. The area of a rectangle is 4 cm less than the area of the square. If length of the rectangle is 15 cm, then its perimeter is​..?

Answers

Answered by devinamita817
0

Answer:

30.54

Explanation:

area of rectangle = 4cm

length of rectangle =15cm

breadth of rectangle =?

area of rectangle =length×breadth

4 = 15×x

4÷15 = x

0.27 =x

therefore, perimeter of rectangle= 2(l+b)

= 2×(15+0.27)

= 2×15.27

= 30.54

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Answered by singlesitaarat31
3

 \huge \red {\boxed  {\boxed {\mathbb {QUESTION}}}}

The perimeter of a square is 44 cm. The area of a rectangle is 4 cm less than the area of the square. If length of the rectangle is 15 cm, then its perimeter is..?

 \huge \purple {\boxed  {\boxed {\mathbb {ANSWER}}}}

 \huge \blue {\underline  {\underline {\mathbb {48 cm.}}}}

 \huge \pink {\boxed  {\boxed {\mathbb {EXPLAINATION}}}}

 \huge \purple {\boxed  {\boxed {\mathbb {GIVEN}}}}

  • Perimeter of Square = 44 cm.

  • Area of Rectangle is 4 cm² less than Area of Square.

  • Length of Rectangle = 15 cm.

 \huge \purple {\boxed  {\boxed {\mathbb{PERIMETER\:OF\:SQUARE:- }}}}

  • => Perimeter of Square = 4 × Side

  • => 44 cm = 4 × Side

Dividing both term by 4

 \huge \green {\boxed  {\boxed {\mathbb {SIDE = 11CM }}}}

[•_•] <============> [•_•]

 \huge \purple {\boxed  {\boxed {\mathbb {AREA\:OF\:SQUARE:- }}}}

  • => Area of Square = (Side)²

  • => Area of Square = (11 cm)²

  • => Area of Square = (11 cm × 11 cm)

  \green {\boxed  {\boxed {\mathbb {AREA\:OF\:SQUARE=121CM°2 }}}}

[•_•] <============> [•_•]

 \huge \purple {\boxed  {\boxed{\mathbb{ AREA\:OF\:RECTANGLE:- }}}}

  • => Area of Rectangle = Length × Breadth

  • => Area of Square – 4 = 15 cm × Breadth

  • => 121 cm² – 4 cm² = 15 cm × Breadth

  • => 116 cm² = 15 cm × Breadth

Dividing both term by 15 cm.

 \green {\boxed  {\boxed {\mathbb { BREADTH=7.73CM }}}}

[•_•] <===========> [•_•]

\huge\purple{\boxed{\boxed{\mathbb{PERIMETER\:OF\:RECTANGLE:- }}}}

  • => Perimeter = 2(Length + Breadth)

  • => Perimeter = 2(15 cm + 7.73 cm)

  • => Perimeter = 2 × 22.73 cm

  • => Perimeter = 45.46 cm.

  \green {\boxed  {\boxed {\mathbb { PERIMETER=45.46CM }}}}

Perimeter of Rectangle will be 45.46cm.

.

 \huge \green {\boxed  {\boxed {\underline  {\mathbb {SINGLE\:STAR}}}}}

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