Question

The perimeter of a square is 48 cm .Find the length of its diagonal​

Answer 1

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

The perimeter of a square is 48 cm .Find the length of its diagonal

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{solution}}}}}}}}$

${\bold{\underline{\pink{Given}}}}$

• perimeter of the square = 48 cm

${\bold{\underline{\pink{Find}}}}$

• diagonal of the square

${\bold{\underline{\pink{Solution}}}}$

perimeter = 48cm

${\bold{\blue{\boxed{\bf{Perimeter\:of\:square = 4 \times side }}}}}$

4 * side = 48

side = 48 /4cm

side = 12cm

${\bold{\blue{\boxed{\bf{Diagonal\:of\: square = s \sqrt 2}}}}}$

diagonal = 12 √2 cm

${\bold{\blue{\boxed{\bf{\sqrt 2 = 1.414 }}}}}$

diagonal = 12 * 1.41

diagonal = 16.92cm

${\bold{\blue{\boxed{\bf{\dag diagonal = 16.92cm }}}}}$

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THANK YOU❤

Answer 2

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Perimeter = 48cm

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Diagonal = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

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$\sf{\orange{\boxed{\bold{each\: side = \dfrac{perimeter}{4}}}}}$ --- ( i )

$\sf{\orange{\boxed{\bold{Diagonal = each\:side\sqrt{2}}}}}$ ---- ( ii )

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• From eq ( i ) and ( ii )

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$\sf{\red{\boxed{\bold{Diagonal = \dfrac{perimeter}{4}\sqrt 2 }}}}$

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$\sf: \implies\: {\bold{ Diagonal = \dfrac{48}{4} \sqrt {2}}}$

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$\sf: \implies\: {\bold{ Diagonal = 12\sqrt{2}}}$

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• value of √2 is 1.414

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$\sf: \implies\: {\bold{ Diagonal = {12 \times 1.414 }}}$

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$\sf: \implies\: {\bold{ Diagonal = 16.92cm }}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Diagonal of the given square is 16.92cm