Question

the perimeter of a square is 48 m .the area of a rectangle is 4sq m less than the area of the given square .if the length of rectangle is 20m ,find its breadth


plz answer

Answer 1

Answer:

breadth of rectangle will be 7m^2

Step-by-step explanation:

Here≈

Perimeter of square =4×side=48m

so side of square = 12 m

Area of square = side × side = 12×12=144m^2

As we have given that area of rectangle is 4m^2

less than area of square.

So area of rectangle =144-4=140m^2

Area of rectangle =Length × Breadth =140

Si bteadth of rectangle = area/length

≈140/20

≈7m

Hence the breadth of rectangle is 7 m. ✔️✔️✔️

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Answer 2

Question:

The perimeter of a square is$48m$.The area of a rectangle is $4m²$less than the area of the given square. If the length of the rectangle is $20m$, find it's breadth.

Answer:

ATQ

Square's perimeter =$48 m$

so, side of square = $\frac{48}{4}m$

=$12m$

Therefore

Area of square = (side)²

= $(12)²m$

= $144m²$

Now,

Here in the sum said that area of the rectangle is $4m²$ lesser than the square's area . So, $144m²- 4m²$ or $140m²$ is the area of the rectangle.

Again,

Length of the rectangle = $20m$

Area of the rectangle = $140m²$

therefore,

Breadth = $\frac{area}{length}$

= $\frac{140m²}{20m}$

= $7m$