Question

the perimeter of a square is increased by 20%.what is the increase of its area​

Answer 1

Answer:

Let the p of square be 4x.

:.Each side of square =4x/4=x

:.Area of square=x^2

Now,

When p is increased by 20%,

New p=120×4x/100=4.8x

:.Each side of the new square=4.8x/4=1.2x

Area of the new square=(1.2x)^2=1.44x^2

:.Increasd in area=1.44x^2-x^2=0.44x^2

:.Percentage increase in area=((0.44x^2)100/x^2)%=44%

Answer