Question

The perimeter of a square is increased by 25%. Find the percentage of increase in its area.​

Answer 1

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Let each side of the square be a.

Then,

Area = a²

New side

=125a/100

= 5a/4.

New area

= (5a/4)² 

= (25a²/16)

 

Increase in area

= 25a²/16−a²

=9a²/16

Increase%

= [9a²/16*1/a²*100]%

= 56.25%.