Question

The perimeter of a square photo frame is 24cm.
1.find the length of its sides.
2.the area of the photo frame.

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Lenght\:of\:sides=6\:cm}}$

$\large\red{\boxed{\sf Area(A)=36\:{cm}^{2} }}$

$\huge\underline\blue{\sf Solution:}$

1. Find the Lenght of photo frame side .

$\large\underline\pink{\sf Given: }$

• Perimeter of photo frame (P)=24cm

$\large\underline\pink{\sf To\:Find: }$

• Lenght of side of photo frame(a)=?

We know that ,

$\large{♡}$$\large{\boxed{\sf Perimeter\:of\:square (P)=4a }}$

On Putting value :-

$\large\implies{\sf 24=4×a}$

$\large\implies{\sf a={\frac{24}{4}}}$

$\large\implies{\sf a=6cm }$

$\huge\red{♡}$$\large\red{\boxed{\sf Lenght\:of\:sides=6\:cm}}$

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2) Find Area of the photo frame .

$\large\underline\pink{\sf Given: }$

• Side of photo frame (a) = 6 cm

$\large\underline\pink{\sf To\:Find: }$

• Area of photo frame (A) = ?

We know that ,

$\large{♡}$$\large{\boxed{\sf Area\:of\:square(A)={a}^{2} }}$

On Putting value :-

$\large\implies{\sf A = 6×6}$

$\large\implies{\sf 36{cm}^{2}}$

$\huge\red{♡}$$\large\red{\boxed{\sf Area(A)=36\:{cm}^{2} }}$

Answer 2

$\large \sf \underline{ \underline{ \: Solution : \: \: \: }}$

Given ,

Perimeter of square = 24 cm

Let ,

Side = a

We know that ,

$\sf \large\fbox{ \fbox{Perimeter \: of \: square = 4a \: \: }}$

$\sf \to 24 = 4a \\ \\ \sf \to a = 6 \: cm$

Thus , 6 cm is the length of its sides

Now ,

$\large \sf\fbox{ \fbox{ \: Area \: of \: square = {(Side)}^{2} \: }}$

$\to \sf Area = {(6)}^{2} \\ \\ \to \sf Area = 36 \: {cm}^{2}$

Thus , 36 cm² is the area of the photo frame