Math, asked by IMALOSER44, 5 days ago

The perimeter of a square piece of land is 20 m. A cow is standing in the middle of the square piece of land, as shown in the figure. What is the minimum distance that the cow has to travel in order to go out of the field and drink water?​

Answers

Answered by yousufnakhawa
0

Answer: 7.071m

Step-by-step explanation:

So, since the cow has to walk out of the square field of 20m, we will have to use Pythagorean theorem. Since the perimeter is 20m, each side will be 5m. Now, we need to find the hypotenuse so that we can get half of the diagonal of the square field

x^2= 5^2+5^2

x^2= 25+25

x^2= 50

x= 7.071m

Therefore, the cow has to walk 7.071 m to go out of the field and drink water.

Answered by chandan454380
0

Answer:

The cow has to travel minimum 5/√2 m through diagonal to go out of the field .

Step-by-step explanation:

Let length of a square field be a m

then 4a = 20 m

⇒ a = 5 m

diagonal length of the square is 5√2 m

half length of the diagonal is 5/√2 m

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