Question

the perimeter of a trapezium is 104 m its non parallel sides are 18 m and 22 and its altitude is 16 find the area of the trapezium​

Answer 1

There will be 2 Rt. triangles and a rectangle. The basis of the triangles

are v18^2-16^2 = 8.2mand

v22,^2-16^2 = 15.1

So the perimeter will be 18+22+8.2+15.1+ 2x = 104,

whereis the length of the rectangle

= 63.3+2x=lo4

2x = 104=63.3=40.7

x = 40.7/2=20.35m

Area of the trapezium

h=16, parallelside I,)20.35

2)20.35 +8.2+15.1=43.65m

Area of trapezium=16(20.35 +43.65)/2 =512m2