the perimeter of a trapezium is 52 cm if its non - parallel sides are 10 cm each and its altitude is 8 cm find the area of the trapezium
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From Pythagoras theorem 10² = 8² - x² x² = 36 x = 6
so, base of the right-angled triangles is 6cm.
The shorter parallel side of the trapezium = x,
The longer parallel side will = x + 2*6 = x + 12
P = x + x + 12 + 10 + 10 = 52 2x = 20 x = 10
Finally the side lengths of the trapezium are 10, 10, 10 and 22.
A = h/2(a + b) = 8/2 x 32 = 4 x 32 = 128cm²
so, base of the right-angled triangles is 6cm.
The shorter parallel side of the trapezium = x,
The longer parallel side will = x + 2*6 = x + 12
P = x + x + 12 + 10 + 10 = 52 2x = 20 x = 10
Finally the side lengths of the trapezium are 10, 10, 10 and 22.
A = h/2(a + b) = 8/2 x 32 = 4 x 32 = 128cm²
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