The perimeter of a trapezium is 52 cm. If its non parallel sides are 10 cm each and its altitude is 8cm, find the area of the trapezium.
Answers
Answer:
A=(32×8)/2=128 area A=128
Step-by-step explanation:
Area of a trapezium is A=(B+b)×h/2 where
B is the large paralel line
b is the small paralel line
h is altitude
P is perimeter and c the nonparalel line
P=a+b+2c from this a+b=P-2c a+b=52-20
a+b=32
A=(32×8)/2=128 area A=128
Answer:
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Step-by-step explanation:
By Using Pythagoras Theorem:
Substitute in the values of the non-parallel sides and the Altitude
=> 10^2 = 8^2 - x^2
=> x^2 = 36
=> x= 6
therefore the base of the right angled triangle is 6cm
If we let the shorter parallel side of the trapezium =x the longer parallel side will be = x+ 12
p => x+x +12 +10 +10
p=> x+x +12+10+10
p=> 2x = 20
p=> x= 10
therefore the side length of the trapezium are 10, 10, 10, 22
A => H/2(a+b)
=> 4×32
=> 128 cm^2
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