The perimeter of a triangle 120cm and it`s sides are in the ratio 5:12:13.Find the area of the triangle?
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Given : Perimeter oF Triangle = 10 cm
Ratio of sides =5:12:13
Let the sides be 5x, 12x, 13x
To Permieter 5x+12x+13X = 120 Cm ⇒ x=4cm
So Sides are = 5x4 = 20cm Simlarly other Sides are 48cm and 52cm
Area of Triangle = √S(S-a)(S-b) S-c)
S = 120/2 = 60cm
Area of Triangle = √60(60-20)(60-48)(60-52)
On SImplification
Area Of Triangle = 480 cm²
Ratio of sides =5:12:13
Let the sides be 5x, 12x, 13x
To Permieter 5x+12x+13X = 120 Cm ⇒ x=4cm
So Sides are = 5x4 = 20cm Simlarly other Sides are 48cm and 52cm
Area of Triangle = √S(S-a)(S-b) S-c)
S = 120/2 = 60cm
Area of Triangle = √60(60-20)(60-48)(60-52)
On SImplification
Area Of Triangle = 480 cm²
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