The perimeter of a triangle ABC is 12 3/4 m. If AB=4 1/3m, BC=5 1/4m, find AC
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Perimeter of the triangle is: P=12 3/4 m=51/4 m.
AB=4 1/3 m=13/3 m and BC=5 1/4 m=21/4
P=AB+BC+AC
or, 51/4=13/3+21/4+CA
or, AC=51/4-(13/3+21/4)
or, AC=51/4-(52+63)/12
or, AC=51/4-115/12
or, AC=(153-115)/12
or, AC=38/12
or, AC=19/6
or, AC=3 1/6 m Ans.
AB=4 1/3 m=13/3 m and BC=5 1/4 m=21/4
P=AB+BC+AC
or, 51/4=13/3+21/4+CA
or, AC=51/4-(13/3+21/4)
or, AC=51/4-(52+63)/12
or, AC=51/4-115/12
or, AC=(153-115)/12
or, AC=38/12
or, AC=19/6
or, AC=3 1/6 m Ans.
Answered by
3
Answer:
Perimeter of the triangle is: P=12 3/4 m=51/4 m.
AB=4 1/3 m=13/3 m and BC=5 1/4 m=21/4
P=AB+BC+AC
or, 51/4=13/3+21/4+CA
or, AC=51/4-(13/3+21/4)
or, AC=51/4-(52+63)/12
or, AC=51/4-115/12
or, AC=(153-115)/12
or, AC=38/12
or, AC=19/6
or, AC=3 1/6 m Ans.
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