Question

The perimeter of a triangle ABC is 6 times the arithmetic mean of the sines of its angles. If the side b is 2, then the angle B is

Answer 1

Answer:

The perimeter of a △ABC is 6 times the arithmetic mean of the sines of its angles. If the side a is 1, then the angle A is

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

SOLUTION

We have a+ b + cb

=> 6(sinA + sinB + sinC)/3

=> k(sinA + sinB + sinC) = 2(sinA + sinB + sinC),

sinC),where K= a/sinA = b/sinB = c/sinC

sinC

=> K = 2 (∵sinA+sinB+sinC ≠ 0)

=> a/sinA = 2

=> sinA = 1/2

=> A = π/6