Question

The perimeter of a triangle is 12 units with vertices (0, 4), (0, 0) and ________

Answer 1

Answer:

(3,0)

Step-by-step explanation:

when the co-ordinates of a right angle triangle are (0,0) , (0,4) & (3,0)

The length of each side of triangle would be 3, 4 and 5 respectively.

Perimeter = 3 + 4 + 5 = 12 units

Answer 2

Answer:

The vertices of a triangle are (0, 4), (0, 0) and (3, 0).

The perimeter of ΔAOB = Sum of the length of all its sides:

= distance between (OA+OB+AB)

Distance between the points (x^1,y1) and (x^2, y^2) is given by,

d = √ ((x^2 – x^1)2 + (y^2 – y^1)2)

To determine

Distance between A(0, 4) and O(0, 0) + Distance between O(0, 0) and B(3, 0) + Distance between A(0, 4) and B(3, 0)

$\sqrt{(0 - 0) ^{2} + (0 - 4) ^{2} } + \sqrt{3 - 0) ^{2} + (0 - 0) ^{2} } + \\ \sqrt{0 + 16 + \sqrt{9 + 0} } + \sqrt{(3) ^{2} + \sqrt{(4)} ^{2} } 4 + 3 + \\ \sqrt{9 + 16} 7 + \sqrt{25} 7 + 5 = 12$