Question

The perimeter of a triangle is 12cm and it's hypotenuse is of 5cm find it's area and calculate the sides

Answer 1

perimeter 12
sum of other two sides other than hypotenuse is 12 - 5 = 7 3 + 4 = 7 according to the triplet Pythagoras Theorem 345 area will be equal to 6 CM square this can be calculated using heron's formula hope this helps you!!!

Answer 2

here you go ☆☆

let triangle be ABC

perimeter of ABC = 12

AB + BC + CA = 12

Let the two sides of the triangle be x and y.

x + y + 5 = 12 _________(1)
x^2 +y^2 = 5^2 _________(2)

y = 7 - x _________ (3)

Substituting:(3) in (2)

x^2 + (7 - x)^2 = 25

x^2 + 49 - 14x + x^2 = 25

2x^2 - 14x + 24 = 0

2(x^2 - 7x + 12) = 0

2(x - 3)(x - 4) = 0

x = 3 and 4

The two sides measure 3 and 4cm.

The area is given by A = (B x H)/2 where B and H are the two sides .

A = (3 x 4)/2

A = 6 square centimetres.

In summary:

The triangle has sides of 3, 4 and 5 centimetres. The area is of12" cm"^2

hope it helps you........